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Mathematics 15 Online
OpenStudy (anonymous):

Find the limit for a(n) = [cos(pi*n)]/n^2 as n approaches infinity. This is what I did. Can anyone confirm that I'm on the right track? http://i.imgur.com/6Qlrwb7.jpg I misspelled squeeze.

OpenStudy (solomonzelman):

yes, 0 makes sense.

OpenStudy (solomonzelman):

because cosine will be some number between -1 and 1, and n^2 will get infinitely large.

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