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OpenStudy (anonymous):
Find the limit for a(n) = [cos(pi*n)]/n^2 as n approaches infinity. This is what I did. Can anyone confirm that I'm on the right track? http://i.imgur.com/6Qlrwb7.jpg I misspelled squeeze.
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OpenStudy (solomonzelman):
yes, 0 makes sense.
OpenStudy (solomonzelman):
because cosine will be some number between -1 and 1, and n^2 will get infinitely large.
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