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what is the short way to solve (2+h)^3
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Binomial theorem is awesome :)
\[(a+b)^3 = (a+b)(a^2 + 2ab + b^2) = a^3 + 3a^2b + 3ab^2 + b^3\]
the exponents of a start at 3 and go down: 3, 2, 1, 0 and the exponents of b go upwards: 0, 1, 2, 3
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