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Use summation notation to write the series: 52+49+46+… for 8 terms Plz help i give medals
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the series forms an AP in which 1st term is 52 and common diff is -3 \[ \sum_{n=1}^{8}4 (2(a) + (n-1)(d)\])=sum.. n=8 d=-3 a=52
hey sorry just saw this!
its ok.. :)_
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