Question

Please explain

Answer 1

i have found \[f'(\theta)=-2\sin \theta+2\sin \theta(\cos \theta)\]

Answer 2

\[f'(\theta)=2\sin \theta(\cos \theta-1)\]

Answer 3

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=3&ved=0CC0QFjAC&url=http%3A%2F%2Fopenstudy.com%2Fupdates%2F4ea850f3e4b0a7d51421ee6b&ei=2MzrVO--BsWdNtXzgAg&usg=AFQjCNH7TkpmOcFFC92-r6Ca7Rq_jaUm5w&sig2=lOljxflX-1N1ZoAfYOCXdA&bvm=bv.86475890,d.eXY

Answer 4

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=6&ved=0CEAQFjAF&url=https%3A%2F%2Fanswers.yahoo.com%2Fquestion%2Findex%3Fqid%3D20091027161211AAAN4pW&ei=2MzrVO--BsWdNtXzgAg&usg=AFQjCNEMbw17Z-bSLcmBLjmNZMs3GP5-Ag&sig2=cEuRCA229RyFdieJSHtZmA&bvm=bv.86475890,d.eXY

Answer 5

so, basically i reach this point where \[1=\cos \theta\]
to find theta ..i do this
\[\cos ^{-1} (1)= \theta\]
and I get zero...why

Answer 6

okay

Answer 7

can you explain?

Answer 8

yes

Answer 9

please do

Answer 10

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Answer 11

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Answer 12

i have seen what he has done but i do not understand how he got pi