Question

The perimeter of a rectangle is 256 inches. How long are the sides if the length exceeds the width by 16 inches?

Mark lets x represent the width of the rectangle and writes the equation 2x + 2(x + 16) = 256. Solving for x, the width of the rectangle is

56
60
68

Answer 1

So in order to solve this problem you need start compiling everything together. When you simplify the above equation, you'll get 4(x+8)=256.

Then you'll distribute the 4 and you'll get 4x+32=256.
Now you subtract 32 so you'll get 4x=224
Divide both sides by 4 and you'll get "56" as your final answer.

Hope that helps.

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