Question

A family has 8 girls and 4 boys. A total of 2 children must be chosen to speak on the behalf of the family at a local benefit. What is the probability
that 1 girl and 1 boy will be chosen?

Answer 1

HI!!

Answer 2

8 ways to choose a girl
4 ways to choose a boy
and \(\binom{12}{2}=\frac{12\times 11}{2}=6\times 11=66\) ways to choose two out of 12

Answer 3

so
\[\frac{8\times 4}{66}\] is your probability

Answer 4

Thank you so much, I really appreciate your help

Answer 5

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