A family has 8 girls and 4 boys. A total of 2 children must be chosen to speak on the behalf of the family at a local benefit. What is the probability
that 1 girl and 1 boy will be chosen?

Question

A family has 8 girls and 4 boys. A total of 2 children must be chosen to speak on the behalf of the family at a local benefit. What is the probability
that 1 girl and 1 boy will be chosen?

misty1212 · Answer

HI!!

misty1212 · Answer

8 ways to choose a girl
4 ways to choose a boy 
and $\binom{12}{2}=\frac{12\times 11}{2}=6\times 11=66$ ways to choose two out of 12

misty1212 · Answer

so 
$$\frac{8\times 4}{66}$$ is your probability

anonymous · Answer

Thank you so much, I really appreciate your help

misty1212 · Answer

$$\color\magenta\heartsuit$$