Question

Chapter 2:Forces and Motion
@mathmath333

Answer 1

where are you with your maths? do you get this:

\[s = \int\limits v dt\]

IOW you need to calc the NET area of the graph - ie net area between the line and the t- axis.

Failing that, you can just break up the trip into bits, calc the ave velocity and time take for each and do it the messy way.

Answer 2

\(s = \int\limits v dt\) ?

Answer 3

distance is integral of velocity wrt time. forgt it if you haven't done this yet. just break the journey into bits, each with its own ave velocity and time period and slog it out.

Answer 4

Can u pls show me the working @IrishBoy123 ?

Answer 5

@IrishBoy123

Answer 6

OK, a snippet but there are rules here about doing other people's work for them:

between t = 2 & t = 3, the average velocity is (30 + 0)/2 = 15m/s. distance travelled in that (2 - 1) = 1 s period = 15/1 = + 15m.

do this for the other periods too and add them up. note that the velocity for the period 4 < t < 6 sec is -ve, it it travels backwards, so that needs to be deducted from the total, not added.

Answer 7

How did u get the distance travelld(2-1)=1 s period ? @IrishBoy123

Answer 8

@IrishBoy123

Answer 9

Can i try it? @MARC_

Answer 10

sure :)

Answer 11

First i wanna find out the distance travelled by first 2 sec

Answer 12

okay

Answer 13

Its an area of this rectangle

Answer 14

60 ?

Answer 15

\[=30\times2\]

Answer 16

Ya. U r right

Answer 17

so what should we do next?

Answer 18

Wts the area of next triangle?

Answer 19

15

Answer 20

Ya correct!

Answer 21

what should we do next?

Answer 22

Frm 3sec to 4 sec it travells no distance

Answer 23

okay

Answer 24

Frm 4 sec to 6 sec it travells distance=?

Answer 25

\[=\frac{ 1 }{ 2 }\times-30\times2\]

Answer 26

Area of last triangle=?

Answer 27

-30

Answer 28

Ya correct!!

Answer 29

Next step,what should we do?

Answer 30

Sum of all area=?

Answer 31

15

Answer 32

After that,what should we do?

Answer 33

Not 15

Answer 34

60+15+0-30=?

Answer 35

45

Answer 36

Thnx @shamim ^_^

Answer 37

U r most welcome!!!!!

Answer 38

:)

Answer 39

Glad to help!!!