The new motorcycle license plate format issued by the Land Transportation Office consists of two letters from the English alphabet and four digits from 0 to 9. A witness of a riding-in-tandem crime reported to the police that he can only remember the first two letters of the license plate, E E _ _ _ _. He was also certain that the four digits of the license plate are distinct, and 1 is not included if 4 is included, and vice versa. If the police officer searches for the motorcycle, how many possible license plate numbers does he have to consider? Calling ganeshie8 hihi. :)
if there is a 1 included then there are 8 numbers (0,2,3,5,6,7,8,9) from which any 3 can be taken That is 8P3 possible permutations.
= 8*7*6 = 336 ways also the 1 can be in any of 4 positions so total ways = 4 * 336 The same reasoning can be applied if there is a 4 in the last 4 numbers
So, the total number of license numbers is, (4 x 336) x 2 + 8P4 = 4368
4368 is right!
Another way to work it is : Total four digit numbers = 10P4 Four digit numbers with both 4 and 1 = 4P2*8P2 So the desired number of license number = 10P4 - 4P2*8P2
I dont follow that why 8P4?.
i'm not saying you guys are wrong. Stats is not my strong point.
number of four digit numbers "without" 4 or 1 = 8P4
I got 8P4 from the case where 1 and 4 are both not included. So i guess that's why Wow Mr. Ganeshie, we got the same answer. But can you please explain? Haha. I did not kind of understand it
oh yes - I assumed that 1 or 4 had to be there - but thats not the case of course.
which part you're looking at ? :)
Mr ganeshie, do you know any online sites where I can study combinatorics or any other branch of mathematics? High school level >:)
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