Question

I really need some help on this question. It wants me to write this equation, 3x^2-9x+38=2x^2+18, in standard form (ax^2+bx+c=0, I think) and then factor the resulting equation.

Answer 1

I got it

Answer 2

3x^2-2x^2-9x=18-38
x^2-9x=-20

Answer 3

@hsedward43