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What is the area of this figure?
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Figure/
*Figure?
We can split this into a trapezoid and a triangle.
Oh I know how to do those!
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Triangle: \(A = \dfrac{1}{2} b h\) \(A = \dfrac{1}{2}(18)(12)\) Simplify
So the triangle would be 108 right?
Trapezoid: \(A = \dfrac{1}{2}(b_1 + b_2) h\)
Correct.
\(A = \dfrac{1}{2}(14 + 18) (5)\) Simplify
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And the trapezoid would be 80 right?
Total height is 17, and the triangle's height is 12, so I subtracted 17 - 12 to find the height of the trapezoid.
Correct, now add the two areas together
188 is the answer?
Yep
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