Question

picture below pls help

Answer 1

@Directrix hey pls help

Answer 2

@iambatman hey pls help me

Answer 3

@jim_thompson5910 hey can you please help me

Answer 4

@calculusxy hey can you help me pls

Answer 5

The area of a circle is \[\Large A = \pi*r^2\]

Answer 6

yes

Answer 7

they gave you the radius in terms of t

basically it's a function that measures what the radius is at any given t value

Answer 8

so you plug in \[\Large r(t) = 200\sqrt{t}\] and simplify

Answer 9

what do you mean
plug in R(t) into the area?

Answer 10

\[\Large A = \pi*r^2\]

\[\Large A = \pi*(r )^2\]

\[\Large A = \pi*(r(t) )^2\]

\[\Large A = \pi*(200\sqrt{t} )^2\]

\[\Large A = ???\]

Answer 11

i think i can leave it like that

Answer 12

no you should simplify

Answer 13

you have one more step to go

Answer 14

alright i don't know how to do that

Answer 15

square 200 to get ???

Answer 16

14.1

Answer 17

not square root

Answer 18

this is what i mean 200^2 = 200*200 = ???

Answer 19

40000

Answer 20

and what do i do after ?

Answer 21

square \(\Large \sqrt{t}\) to get ???

Answer 22

t?

Answer 23

yep

Answer 24

i honesty don't know.. does it stay at t?

Answer 25

\[\Large A = \pi*r^2\]

\[\Large A = \pi*(r )^2\]

\[\Large A = \pi*(r(t) )^2\]

\[\Large A = \pi*(200\sqrt{t} )^2\]

\[\Large A = 40000\pi t\]

Answer 26

Thank you so much!!!

Answer 27

np