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OpenStudy (anonymous):
Calculate the pH of 10.0 mL of 0.10 M HCl plus 5.0 mL of 0.10 M NaOH (strong acid+strong base)
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OpenStudy (sweetburger):
Im not sure if this is correct but the pH might be in the region of 1.47 I think
OpenStudy (anonymous):
It was 1.48 - I had already gotten it, just had a slight error gave me 1.50. Thanks :)
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