check my answers
Use the Distributive Property and simplify the expression. 4 + 2(3x – 1) + 9 A. 6x + 15 B. 3x + 14 C. 6x + 11 D. 5x + 14
i choose d
Which is 1024 written as a power of a number? A. 54 B. 2564 C. 5122 D. 45
i choose a
What is the value of 4a3 – 2b2 + 5 when a = 3 and b = −2? i put 6
Do you know what the distributive property is?
It's a formula where you multiply a term and two or more terms inside of a parentheses.
but i'm not good at it
\(\sf\Large Distributive~Formula\\a(b+c)=ab+ac\)
ok
my brother said that the first one is 6x + 11
but i choose a...
This is our question. \(\Large\sf4 + 2(3x - 1) + 9\) This should be our first step. Lets distribute the terms in red :) \(\Large\sf4 + \color{red}{2(3x -1)} + 9\)
ok :)
So using this formula \(\sf a(b+c)=ab+ac\) What is \(\color{red}{\sf 2(3x-1)}\)
1/3
\(\sf a(b-c)=ab-ac\) is what we have to use. \(\sf 2(3x-1)\) So \(\sf a =2\\b=3x\\c=1\) Sp plug in those values into \(\sf a(b-c)=ab-ac\)
I checked your answers, and none were correct.
This time be more careful and focused.
And that was why I was trying to take him step by step, but he disappeared .-.
Yes, I noticed that, starting out with the first one. Definitely some background missing, looked more like guessing.
Maybe they will get serious about learning and return after a good review. The assortment of questions looked like some sort of qualification quiz.
Gotta go and meet the school bus. good day.
sorry, i had to help someone
\(\color{blue}{\text{Originally Posted by}}\) @TheSmartOne \(\sf a(b-c)=ab-ac\) is what we have to use. \(\sf 2(3x-1)\) So \(\sf a =2\\b=3x\\c=1\) Sp plug in those values into \(\sf a(b-c)=ab-ac\) \(\color{blue}{\text{End of Quote}}\)
ok
So... plug in the values and solve it...
kk
i keep getting 1/3
Thats not even possible .-.
then i got this (-2+6 x)
umm no :/
\(\color{blue}{\text{Originally Posted by}}\) @TheSmartOne \(\color{blue}{\text{Originally Posted by}}\) @TheSmartOne \(\sf a(b-c)=ab-ac\) is what we have to use. \(\sf 2(3x-1)\) So \(\sf a =2\\b=3x\\c=1\) Sp plug in those values into \(\sf a(b-c)=ab-ac\) \(\color{blue}{\text{End of Quote}}\) \(\color{blue}{\text{End of Quote}}\) if we plug it in we get \(\sf 2(3x-1)=2\times 3x-2\times 1\) What is 2x3 and what is 2x1 =?
And no reply was ever given...
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