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Mathematics 7 Online
OpenStudy (anonymous):

check my answers

OpenStudy (anonymous):

Use the Distributive Property and simplify the expression. 4 + 2(3x – 1) + 9 A. 6x + 15 B. 3x + 14 C. 6x + 11 D. 5x + 14

OpenStudy (anonymous):

i choose d

OpenStudy (anonymous):

Which is 1024 written as a power of a number? A. 54 B. 2564 C. 5122 D. 45

OpenStudy (anonymous):

i choose a

OpenStudy (anonymous):

What is the value of 4a3 – 2b2 + 5 when a = 3 and b = −2? i put 6

TheSmartOne (thesmartone):

Do you know what the distributive property is?

OpenStudy (anonymous):

It's a formula where you multiply a term and two or more terms inside of a parentheses.

OpenStudy (anonymous):

but i'm not good at it

TheSmartOne (thesmartone):

\(\sf\Large Distributive~Formula\\a(b+c)=ab+ac\)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

my brother said that the first one is 6x + 11

OpenStudy (anonymous):

but i choose a...

TheSmartOne (thesmartone):

This is our question. \(\Large\sf4 + 2(3x - 1) + 9\) This should be our first step. Lets distribute the terms in red :) \(\Large\sf4 + \color{red}{2(3x -1)} + 9\)

OpenStudy (anonymous):

ok :)

TheSmartOne (thesmartone):

So using this formula \(\sf a(b+c)=ab+ac\) What is \(\color{red}{\sf 2(3x-1)}\)

OpenStudy (anonymous):

1/3

TheSmartOne (thesmartone):

\(\sf a(b-c)=ab-ac\) is what we have to use. \(\sf 2(3x-1)\) So \(\sf a =2\\b=3x\\c=1\) Sp plug in those values into \(\sf a(b-c)=ab-ac\)

OpenStudy (radar):

I checked your answers, and none were correct.

OpenStudy (radar):

This time be more careful and focused.

TheSmartOne (thesmartone):

And that was why I was trying to take him step by step, but he disappeared .-.

OpenStudy (radar):

Yes, I noticed that, starting out with the first one. Definitely some background missing, looked more like guessing.

OpenStudy (radar):

Maybe they will get serious about learning and return after a good review. The assortment of questions looked like some sort of qualification quiz.

OpenStudy (radar):

Gotta go and meet the school bus. good day.

OpenStudy (anonymous):

sorry, i had to help someone

TheSmartOne (thesmartone):

\(\color{blue}{\text{Originally Posted by}}\) @TheSmartOne \(\sf a(b-c)=ab-ac\) is what we have to use. \(\sf 2(3x-1)\) So \(\sf a =2\\b=3x\\c=1\) Sp plug in those values into \(\sf a(b-c)=ab-ac\) \(\color{blue}{\text{End of Quote}}\)

OpenStudy (anonymous):

ok

TheSmartOne (thesmartone):

So... plug in the values and solve it...

OpenStudy (anonymous):

kk

OpenStudy (anonymous):

i keep getting 1/3

TheSmartOne (thesmartone):

Thats not even possible .-.

OpenStudy (anonymous):

then i got this (-2+6 x)

TheSmartOne (thesmartone):

umm no :/

TheSmartOne (thesmartone):

\(\color{blue}{\text{Originally Posted by}}\) @TheSmartOne \(\color{blue}{\text{Originally Posted by}}\) @TheSmartOne \(\sf a(b-c)=ab-ac\) is what we have to use. \(\sf 2(3x-1)\) So \(\sf a =2\\b=3x\\c=1\) Sp plug in those values into \(\sf a(b-c)=ab-ac\) \(\color{blue}{\text{End of Quote}}\) \(\color{blue}{\text{End of Quote}}\) if we plug it in we get \(\sf 2(3x-1)=2\times 3x-2\times 1\) What is 2x3 and what is 2x1 =?

TheSmartOne (thesmartone):

And no reply was ever given...

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