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Probability
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n(A)=13 n(A (intersects) B)=8 n(A U B)=20 Find n(B)=
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\[n(A\cup B)=n(A)+n(B)-n(A\cap B)\]
plug your numbers in and solve
I don't have B though what do I do?
\[n(A\cup B)=n(A)+n(B)-n(A\cap B)\] \[20=13+n(B)-8\] solve
so 15 is the answer?
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I think the answer is 4. not sure 20 = 13 + n(b) - 8 20 = 13 - 8 n(b) 20 = 5 + n(b) 20/5 = n(b)
@kpcoco
15 is correct
@zarkon how did u do that.
solve for N(B) 20=13+n(B)-8 20-13+8=n(B) 15=n(B)
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