Question

Steve is installing a new window. A diagram of the window is shown below.


Note: Figure not drawn to scale

If a = 33 in and b = 44 in, which of the following is closest to the area of the window?
1,452 in2
2,904 in2
1,879.65 in2
https://app107.studyisland.com/pics/167134q3.png

Answer 1

We need to find the area of the semicircle, which is area of circle/2

Answer 2

okay

Answer 3

I am going to bed after this question

Answer 4

k

Answer 5

Find the area of the rectangle first?

Answer 6

how?

Answer 7

Area of rectangle = length times width

Answer 8

okay 1452

Answer 9

In other words Area of rectangle for this one is a times b

Answer 10

Yes,area of this rectangle is 1452 in^2

Answer 11

Now,find the area of the semi-circle.

Answer 12

#justgotlost

Answer 13

\[Area = \frac{ \pi \times r^2 }{ 2 }\]

Answer 14

so the last answer choies is correct?

Answer 15

r^2 = 33 times 33
pi = 22/7

Answer 16

so t=it's 1,879.65 in2

Answer 17

?

Answer 18

@Bee_see

Answer 19

HELP I GOTTA GO VERY SOON

Answer 20

area of the semicirle = 1710.6
area of rectangle = 1452
just add the two and then approx

Answer 21

what is approx?

Answer 22

B

Answer 23

2,904 in2

Answer 24

that's wrong

Answer 25

it was the last one

Answer 26

ok. can you redo it? I got 1879,65

Answer 27

:(

Answer 28

this sucks

Answer 29

@perl
Kindly help this guy otherwise the asker will get confused for sure.

Answer 30

1,879.65 in2

Answer 31

radius =33/2

Answer 32

If you need help getting the answer: area of rectangle= 33X44=1452. Area of circle: piXr^2= piX(16.5)^2. Divide the answer by 2 and you get 427.64. Add it with 1452. We get 1879.649= 1879.65.

Answer 33

area of semicirle =((33/2)^2*pi)/2