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The function g is defined as @ganeshie8
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\[g:x \rightarrow \frac{ ax+b }{ x },x \neq~k\]
Given that g(2)=3 and g(-2)=5,
find the values of a and of b
\[g(x) = \dfrac{ax+b}{x}\]
se the given points and setup two equations
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okay
\[\frac{ 2a+b }{ 2 }=3,\frac{ b-2a }{ -2 }=5\]
looks good! two equations and two unknowns, you can solve them
\[2a+b=6,-2a+b=-10\]
a=4,b=-2
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Thnx @ganeshie8
yw!
:)
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