Question

the area of a rectangle is 600 in 2. find the dimensions of the rectangle if they are in a ratio of 2:3

Answer 1

based on quadratics

Answer 2

what equation do i make besides xy=600?

Answer 3

@eta

Answer 4

you are given with dimensions ratio..

Answer 5

So, let the dimensions be : \(2x\) and \(3x\)..

Answer 6

Always, use the given ratio to define your dimensions..

Answer 7

So, let the length be : \(3x\) and the width is : \(2x\)..

Answer 8

Use this and find out value of \(x\)..

Answer 9

It will confuse you, for length, take \(l\) and for width, take \(w\)..

Answer 10

3x*2x=600?

Answer 11

yep, good..

Answer 12

\[l = 3x \\ w = 2x \\ lw = 600 \\ 3x \cdot 2x = 600 \\ 6x^2 = 600\]

Answer 13

20in by 30in

Answer 14

Good..

Answer 15

See, take the ratio of dimensions now, you will surely get 2/3..

Answer 16

\[\frac{20}{30} = \frac{2}{3}\]

Answer 17

Do you have options with you?

Answer 18

?

Answer 19

Like 4 answer choices from which you have to choose any one?

Answer 20

do 600 divided by 5 since it is 2+3 600/5 would be 120 so that would be x
120(2): 120(3) = 240: 360 but then you would divide 240 and 360 by 2 since it is a rectangle so it would be 120:180

Answer 21

do you understand??