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A horizontal safely supports a load P that varies jointly as the product of the width W of the beam and the square of the depth D and inversely as the length L. A beam that has a width of 5 in, depth of 12 in, and length of 3 in can safely support 3,120 lb. Determine the safe load in pounds of a beam made from the same material if the beam is 15 in long. The safe load is?
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@ChloeSmith09 i have solved it earlier for u
3120= k.5.12.12/3 P=k.5.12.12/15
P=3120/5
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