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Mathematics 23 Online
OpenStudy (anonymous):

Please help!!! Describe the sampling distribution of x-bar for samples of size 20 drawn from a normal population with a mean of 50 and standard deviation of 4.

OpenStudy (perl):

$$ \Large \mu_\bar{x} = \mu \\ \Large \sigma_\bar{x} = \frac{\sigma }{\sqrt{n}} $$

OpenStudy (perl):

does that make sense?

OpenStudy (perl):

here mu is the population mean and sigma is the population standard deviation n is the sample size

OpenStudy (anonymous):

Yes, Thank you!

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