PLEASE HELP
What is the equation of the graphed line?
Hint: Determine the slope of the line.
y = x
Graph of a line passing through the origin and Quadrants II and IV. Line passes through (1, -5).
@jim_thompson5910 i will attach photo
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OpenStudy (kaloemalia):
jimthompson5910 (jim_thompson5910):
What two points lie on this line?
OpenStudy (kaloemalia):
+6 and -6??
jimthompson5910 (jim_thompson5910):
points are ordered pairs
jimthompson5910 (jim_thompson5910):
of the form (x,y)
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OpenStudy (kaloemalia):
oh haha sorry..
OpenStudy (kaloemalia):
so 6,1 and -6,1?
jimthompson5910 (jim_thompson5910):
see attached
jimthompson5910 (jim_thompson5910):
do you see the points I marked?
OpenStudy (kaloemalia):
oh, okay thank you
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OpenStudy (kaloemalia):
so.. (1,-5)..
jimthompson5910 (jim_thompson5910):
that's one point on it, yes
jimthompson5910 (jim_thompson5910):
use those two points to compute the slope
OpenStudy (kaloemalia):
so is the other one (1,5) ???
OpenStudy (kaloemalia):
I'm out of it
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OpenStudy (kaloemalia):
sorry
jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
look at the graph
OpenStudy (kaloemalia):
I'm sorry i truly don't understand
OpenStudy (kaloemalia):
@jim_thompson5910
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jimthompson5910 (jim_thompson5910):
hopefully you see (0,0) and (1,-5) right?
jimthompson5910 (jim_thompson5910):
on my attachment
OpenStudy (kaloemalia):
okay well i went over it and for the whole thing i got -5???? im sure it's wrong but hopefully it's a start