Question

Check my answer
Solve by factoring or finding square roots
2x^2-3x=0

A. 2, 3
B. 0, 1/2 <--my answer
C. 0, 3/2
D. 2, 3/2

Answer 1

Nope, 0 is correct, but 1/2 is not.

Answer 2

Ok so c is correct..

Answer 3

Yep, you got it.

Answer 4

Thanks

Answer 5

\[\begin{align}
2x^2-3x&=0\\
x(2x-3)&=0\\
x(x-\tfrac32)&=0\\
\qquad&\Downarrow\\
x=0 &\text{ or }x-\tfrac32=0\\
&\qquad \quad x=\tfrac32
\end{align}\]