Mathematics
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OpenStudy (anonymous):
If f(x) varies directly with x, and f(x) = 45 when x = 9, find the value of f(x) when x = 3.
A. 5
B. 9
C. 15
D. 27
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OpenStudy (anonymous):
@iGreen
OpenStudy (igreen):
f(x) = 45
x = 9
Plug them in:
45 = k(9)
45 = 9k
Divide 9 to both sides, what's 45 / 9?
OpenStudy (anonymous):
5
OpenStudy (anonymous):
And your using "K". Does it matter which one you use? Because there is no "K" in the equation
OpenStudy (adi3):
5 is right
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OpenStudy (igreen):
Yes, so the constant is '5'.
No, it doesn't..it just represents the constant..that's how they use it.
OpenStudy (igreen):
Now let's plug in k = 5 and x = 3 and solve for f(x).
f(x) = kx
f(x) = (5)(3)
Multiply 5 * 3
OpenStudy (anonymous):
Ok. I have a few more. Help me with those also?
OpenStudy (adi3):
no wait the method which teacher was t o45/9 = 5
5 * 3 = 15
answer is 15
OpenStudy (adi3):
no no wait I messed up it was for some other subject not fo this one 5 is right
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OpenStudy (anonymous):
:?
OpenStudy (anonymous):
So the answer is 15 @iGreen
OpenStudy (igreen):
Yes, it is.
OpenStudy (adi3):
wht is am right
OpenStudy (adi3):
@iGreen
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OpenStudy (anonymous):
Ok. I have a cpiuple more. Help me with those?
OpenStudy (anonymous):
couple*
OpenStudy (adi3):
guys some one give me medal
OpenStudy (adi3):
pls
OpenStudy (anonymous):
I already gave one to @iGreen Sorry
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OpenStudy (adi3):
redo it
OpenStudy (adi3):
@DelTa-_-LeGEnD