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What is the coefficient of x^2y^3 in the expansion of (2x+y)^5? A. 2 B. 5 C. 40 D. 80 E. It does not exist
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try the 4 th terms = 5C3 (2x)^(5-30 y^3
* that is 5C3 (2x)^(5-3) y^3
= 5C3 4x^2 y^3 now you need to calculate 5C3 * 4
the number of combinations of 3 in 5 nCr = n! ----- (n-r)! r!
so its letter B?
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No 5C3 = (5*4*3*2*1 --------- 2*1 * 3*2*1
and you need to multiply that by 4
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