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solve each equation on the interval [0,2pi] tan3x=square root 3
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@bibby
@Kainui
\[\tan(3x)=\sqrt{3}\]
@jigglypuff314
@sammixboo
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@perl
|dw:1425427021371:dw|
it'll be pi/3 and pi/6?
to get (root(3)) / 1 which is what they want you have a tangent angle of pi/3 so 3x = pi/3
okay i understand that part/
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what next?
what did you get for x?
x=pi/9
then in what quadrants is tangent positive?
3rd
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isnt there more than one equaiton
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