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Evaluate x^-2 for x = -3. I got 1/9 but apparently it was wrong
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\[\Large x^{-2} = \frac{1}{x^2}\] \[\Large (-3)^{-2} = \frac{1}{(-3)^2}\] \[\Large (-3)^{-2} = \frac{1}{9}\] I'm getting the same
i'll go with that too
@jim_thompson5910 @satellite73 Thanks for trying to help (:
It sounds like there's a typo somewhere. So I'd just ask the teacher and s/he will probably agree and give points back.
me too, i would go with \(\frac{1}{9}\)
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in fact, i am sure of it
do they want it expressed as 9^-1?
If every body failed on this problem, I want to join to the group. :)
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