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OpenStudy (anonymous):
sin(2cos^-1 4/5)= step by step
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OpenStudy (agl202):
Do you know that cos^-1(4/5) = sin^-1(3/5) otherwise draw a diagram and convenience yourself!!! Next use Sin2A = 2sinAcosA so the given expression is 2sincos^-1 (4/5)coscos^-1 (4/5) = 2sinsin^-1 (3/5)coscos^-1 (4/5) =2(3/5)(4/5) =24/25
OpenStudy (anonymous):
awesome. thank you!!!
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