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V varies inversely with T and V = 12 when T = 6. Which equation shows this relationship? I got V=72T
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nope "inverse variation" not direct
which equation did u use to find k ??
k = xy
so wouldn't that be k = 12 times 6 and that = 72.
hmm okay so replace k by 72 and then solve for V(y)
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yep k value is right but that not suppose to be v = 72t remember inverse variation is y = k/x
ok so V(y) = 72/x
yep right but remember in this question x is t
ohh ok
inverse variation \[\huge\rm y = \frac{ k }{ x }\] \[\huge\rm y = kx \] direct variation
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so V = 72/t ?
yep |dw:1425453988720:dw|
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