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What is the 22nd term of the arithmetic sequence where a1 = 8 and a9 = 56?
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what have you tried? know the required formulas?
i am confused about what it wants i have a list of formulas next to me
"What is the 22nd term" so you will use n'th term formula "of the arithmetic sequence" of the arithmetic sequence
\(a_n = a_1 +(n-1)d\)
we are given a9 so plug in n= 9 in that formula
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sooo: a of n = a1+(9-1)d
n= 9 so, left side = a9 = 56 and a1 is also given, right!
a1 is 8 right?
yep
56 = 8+8d
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so d is 6
yep, now use the same formula again to find 22d term = a22 just plug in n=22
22nd*
an=8+(22−1)6
is that right?
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so 134??
correct :)
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