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Mathematics 12 Online
OpenStudy (anonymous):

Find the quotient of the link is below -3y5 + 10x2y2 - 4 -15x2y6 + 50x4y3 - 4 3y5 + 10x2y2 - 4 -3xy5 + 10x2y2 - 4

OpenStudy (lunymoony):

Are we missing something? @i_suck_at_school

OpenStudy (anonymous):

OpenStudy (anonymous):

no @LunyMoony

OpenStudy (lunymoony):

I believe that was what we were missing, that attachment, hold on I'll get the answer @i_suck_at_school

OpenStudy (anonymous):

ok thx

OpenStudy (lunymoony):

Ok, so ... 15x2y6 + 50x4y3 - 20x2y divided by 5x2y divide -15x2y6 by 5x2y, we get -3y5 divide 50x4y3 by 5x2y, we get 10x2y2 divide -20x2y by 5x2y, we get -4 So which one is it? :D

OpenStudy (lunymoony):

It is -3y5 + 10x2y2 - 4, so A

OpenStudy (lunymoony):

@i_suck_at_school

OpenStudy (anonymous):

thanks

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