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find side b
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|dw:1425512220125:dw|
I can help u
awesome!
recall your SOH CAH TOA |dw:1425513314220:dw| \(\bf {\color{brown}{ sin}}(\theta)=\cfrac{opposite}{hypotenuse} \\ \quad \\ % cosine {\color{blue}{ cos}}(\theta)=\cfrac{adjacent}{hypotenuse} \\ \quad \\ % tangent tan(\theta)=\cfrac{opposite}{adjacent}=\cfrac{y}{x}\) which one has the angle, the adjacent side, and the hypotenuse "only"?
\[\cos(\theta)?\]
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ahhhh so let us use that one then \(\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\implies hypotenuse\cdot cos(\theta)=adjacent \\ \quad \\ cos(46^o)=\cfrac{b}{10}\implies 10\cdot cos(46^o)=b\)
b=6.946?
yeap
would you mind helping with some more?
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