Question

Find the curvature of y=sec x.

Answer 1

\[k(x)=\frac{ \left| y'' \right| }{ [1+(y')^2]^{3/2} }\]

Answer 2

\[y'=\sec x \tan x\]

Answer 3

\[y''=\sec x(\sec ^{2} x+ \tan ^{2} x)\]

Answer 4

How to find k(x)?

Answer 5

@e.mccormick @ParthKohli @undeadknight26 @Destinymasha

Answer 6

@freckles @sammixboo

Answer 7

I am so sorry! I can't help with this :(

Answer 8

@zepdrix

Answer 9

Hmm I'm a little rusty on my calc 3 stuff :c