Mathematics
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OpenStudy (anonymous):
the result of a number,when decreased by 20% ,is 192.find this number
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OpenStudy (anonymous):
@shamim @Smita12 @SchoolHelpPlease169 @ganeshie8 @queelius @iambatman @ikram002p @inowalst
OpenStudy (inowalst):
@iambatman ??
OpenStudy (anonymous):
can help/?
OpenStudy (shamim):
Let the number is x
OpenStudy (aaronandyson):
Let the number be "x":
Equation:
x - 0.20x = 192?
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OpenStudy (shamim):
So amount of decrease=x*20%=?
OpenStudy (shamim):
Response plz!!!
OpenStudy (shamim):
Anyway
x*20%=x*20/100=0.2x
Right?
OpenStudy (shamim):
So
x-0.2x=192
OpenStudy (shamim):
x=?
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OpenStudy (anonymous):
oh sorry ...wait please
OpenStudy (shamim):
Ok....
OpenStudy (anonymous):
so answer?
OpenStudy (anonymous):
answer would be what?@shamim @AaronAndyson
OpenStudy (anonymous):
@shamim
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OpenStudy (anonymous):
x - 0.20x = 192
OpenStudy (anonymous):
next @Smita12
OpenStudy (anonymous):
x - \[\frac{ 1}{ 5x}\] = 192
OpenStudy (anonymous):
these are in the same line
OpenStudy (anonymous):
it should be 1x / 5
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OpenStudy (anonymous):
\[\frac{ 5x - x }{ 5}\]
OpenStudy (anonymous):
its simple wait u have 20x/100
OpenStudy (anonymous):
so we canceling the "0" andcanceling 10 with 2
OpenStudy (shamim):
U r wrongv@Smita12
OpenStudy (anonymous):
no my method is diff
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OpenStudy (anonymous):
so we get 0.2... next @shamim tell me from dwhere u left plzzz
OpenStudy (shamim):
x-.2x=192
x(1-.2)=192
x*.8=192
x=192/.8
x=?
OpenStudy (anonymous):
how you get 1 and .8 @shamim
OpenStudy (anonymous):
@Smita12 please countinue your procedure
OpenStudy (anonymous):
lol
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OpenStudy (shamim):
U know
x=x*1
Right?
OpenStudy (anonymous):
just tell me first how much did u understand
OpenStudy (anonymous):
x-0.2=192 still
OpenStudy (anonymous):
no @shamim
OpenStudy (anonymous):
it should be x - 0.2x = 192
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OpenStudy (anonymous):
take x as 1
OpenStudy (shamim):
x-0.2x=192
x*1-.2x=192
x(1-.2)=192
x*.8=192
Right?
OpenStudy (anonymous):
1 - 0.2 = 0.8
OpenStudy (anonymous):
so i suppose it is noww 0.8x
OpenStudy (anonymous):
0.8x = 192
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OpenStudy (anonymous):
x = 192/0.8
OpenStudy (anonymous):
thank you very much all of you
OpenStudy (leonardo0430):
^