Question

Can you help me solve the rest of these fractions??

The first fraction will be the original question, second would be what I've solved it to so far.

1. (2/3)^2 2. 2/3^2
1. (2x^6/y^4)^3 2. 2/^18/y^12
1. (3/4)^-2 2. 3^-2/4^-2

PLEASEE Help !

Answer 1

you have 2/3 in brackets all squared
this is the same as 2/3 x 2/3
so use your rules for multiplying fractions

(2x2)/(3x3)

Answer 2

with a negative power, remember that means the whole thing squared, then take the reciprocal (1/ answer)

Answer 3

So for (2/3)^2 ... What you said to do was multiply 2x2 / 3x3 ?

(4/6) ? What do you do with the ^2? And can you help me with the others too.. I honestly don't understand how to do them.

Answer 4

@amorfide