Question

Suppose an isosceles triangle ABC has A=pi/4 and b=c=4. What is the length of a^2?

Please explain. Thank you!

Answer 1

a^2 = (4)^2+(4)^2 - (2 * 4 * 4 * cos(45))

Answer 2

this is an iso so <ACB = ABC = 180 - 45/ 2 = 135 /2 = 67.5
so 4/sin(67.5) = a / sin45
a = 4*sin45/sin(67.5)

Answer 3

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