The sum of five times a number and twice a second number is 18, but the difference of three times the first number and seven times the second number is -22. Find the two numbers using the elimination method. A. -2 and -4 B. -2 and 4 C. 2 and -4 D. 2 and 4
the sum of five times a number lets call it \(x\) so the sum of \(5x\) and two times a second number, lets call it \(y\) so \[5x+2y\] is \(18\)or \[5x+2y=18\]
the difference of 3 times the first number and seven times the second number is \(-22\) translates in to \[3x-7y=-22\]
your job it to solve \[5x+2y=18\\ 3x-7y=-22\]
do you know how to do that?
no
Just let one number is =x Another number is=y
lol then you can't solve this problem you can do it by hand or by machine
you pick
is it D?
\[\{5 a+2 b=18, 3 a-7 b=-22\} , \{a\to 2, b\to 4\} \]
Fivs times of a number x=5x Right?
Join our real-time social learning platform and learn together with your friends!