Question

help please.

Answer 1

i dont know how to solve.

Answer 2

hmm leme fix that quick \(\large {

\begin{array}{llll}
{\color{brown}{ y}}=2x^2-3\\
{\color{brown}{ y}}=3x-1
\end{array}\qquad {\color{brown}{ y}}={\color{brown}{ y}}\quad thus\quad 2x^2-3=3x-1
}\)

Answer 3

well... so
if you haven't covered quadratics.. or system of equations
seems to me this exercise doesn't apply to you then

Answer 4

you may want to cover that section first