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If f(x) = 8x2 − x3, find f '(1) and use it to find an equation of the tangent line to the curve y = 8x2 − x3 at the point (1, 7).
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okay well start by finding f(1). So put in 1 where you see x. \[f(1)=8(1)^{2}-(1)^{3}\] So what do we get?
Alright. I'm going to go to bed. Once you find that you have to find the tangent line to a curve. http://www.math.brown.edu/utra/tangentline.html http://www.mathsisfun.com/calculus/derivatives-introduction.html I hope these resources help. Hopefully someone else will help you.
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