Question

PLZ help!! medal for correct answer!
what is the value of Z so that -9 and 9 are both solutions of x^2+z=103

Answer 1

@nashg you know?

Answer 2

this one to

Answer 3

i got this first question i just need the one on the pic i posted, i aslo posted the wrong answers forthe first one

Answer 4

forget the first question xD

Answer 5

well you need the difference of 2 squares to get the solutions of -9 and 9

so the equation would be

\[x^2 - 81 = 0~~~or~~~~~x^2 = 81\]

so by subtracting z from both sides you need to solve

\[81 = 103 - z\]

Answer 6

and just solve for z

Answer 7

right, i got 22 right?

Answer 8

@campbell_st

Answer 9

is number 4 no solution?

Answer 10

that's correct for z.

Answer 11

ok cool. i assume that because i plugged them in and it dosent make sense

Answer 12

well you know the area is 24 and side lengths are 3b and b

so then using the formula for area of a triangle

\[24 = \frac{1}{2} 3b \times b\]

you can solve for b.

One suggestion is that measurements can only be positive.... so that may help you get the correct answer

Answer 13

so do i plug in answers to see it they fit?

Answer 14

iits 4? cuz 3*4=12 half of 12 is 6 nad 6*4 is 24 right?