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Help with question 7i pleaseee! http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s07_qp_3.pdf
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So, u = sqrt x du/dx = 1/2sqrtx
ok now find dx
I = 1/u^-1/2 (4-u) 2sqrt u du ?
dx = 2x^1/2 du
im talking about the overall.
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ok - bear with me - its been a while since i did these
Aites.
dx = 2u du
i'll have to just do small posts as thers something wrong with the website
wait dx is wht again?
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u = sqrt x so x = u^2 so if we substite in the integral
@welshfella - i get that all the time, the Post button disappears. i have tried Safari, Chrome and it is soooo frustrating.....
yes its murder dx = 2u.du
not dx = u.du - my mistake
delete the wrong one pls. haha thanks.
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