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Trig help!
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sec(theta) = 9 Use identities to find the exact values of cos(theta) csc(theta - pi/2) tan^2(theta)
cos theta = 1/sec theta = 1/9
oh yeah. you just flip them. thanks!
cosec theta = 1/sin theta
cosec (theta -pi/2) = 1 / -sin(pi/2 - theta)
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cosec (theta - pi/2) = - sec theta
tan^2 theta+ sec^2 theta = 1 tan^2theta = 1- sec^2 theta
now u just have to feed in the values and solve
Thanks!
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