Question

find an equation of the tangent to the curve at the point corresponding to the given value of the parameter

Answer 1

x= t-2sint y=t-2cost

Answer 2

0<theta<4pi

Answer 3

dx/dt = 1-2cos(t) dy/dt= 1+ 2sin(t) is this right?

Answer 4

I would find dx/dt
and dy/dt

then (dy/dt)/ (dx/dt)= dy/dx = slope of tangent line

Answer 5

yes, your dx/dt and dy/dt look ok

Answer 6

okay what do i do next?

Answer 7

square root both the dy/dt and dx/dt?

Answer 8

(dy/dt)/ (dx/dt)= dy/dx = slope of tangent line

Answer 9

I am thinking find the equation
y= mx + b

but if we need to find in terms of t, I would have to think about it

Answer 10

okay