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Verify. cscx-tan(x/2)=cotx
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I want to do LHS--->RHS
HI!!
do you know your identities?
i guess you have to dredge up the formula for \[\tan(\frac{x}{2})\] which i can never remember
actually now that i look closer, i am pretty sure it is NOT and identity lets try it with \(\frac{\pi}{3}\)
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cscx = 1/sinx and tan(x/2) = 1-cosx/2 = sinx/1+cosx
\[\csc(\frac{\pi}{3})=2\]\[\tan(\frac{\pi}{6})=\frac{1}{\sqrt3}\]and \[2-\frac{1}{\sqrt3}\neq \cot(\frac{\pi}{3})=\frac{1}{\sqrt3}\] so you cannot prove it
Thank you.
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