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A railroad tunnel is shaped like a semiellipse as shown below The height of the tunnel at the center is 54 ft and the vertical clearance must be 18 ft at a point 8 ft from the center. Find an equation for the ellipse.
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@misty1212
i know i have the points (0,54) and (8,18)
\[\frac{x^2}{a^2} + \frac{y^2}{b^2}=1 \]
we know \(b^2=54\) so we need \(a^2\) plug in the numbers
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\[\frac{8^2}{a^2}+\frac{18^2}{54}=1\] solve for \(a^2\) and that is it
i got this far, i just dont get how to solve for a.
@satellite73
would a=24?
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