Question

trig help!

Answer 1

find the exact value of sec(-3pi/2)

Answer 2

i understand that it would be 90 degrees since its negative but then im confused

Answer 3

\(\bf sec(\theta)=\cfrac{1}{{\color{blue}{ cos}}(\theta)}\qquad \qquad cos(-\theta)=cos(\theta)
\\ \quad \\ \quad \\

sec\left( -\cfrac{3\pi }{2} \right)\implies \cfrac{1}{cos\left( -\frac{3\pi }{2} \right)}\implies \cfrac{1}{cos\left( \frac{3\pi }{2} \right)}\implies ?\)

Answer 4

undefined?

Answer 5

yeap

Answer 6

you really helped me out! thanks a ton!