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Mathematics 19 Online
OpenStudy (anonymous):

An office has 6 employees; there are 5 female employees and 1 male employee. In how many ways can a 3-person committee be created if the committee must include the male employee?

OpenStudy (anonymous):

See, the committee must include the male persons, it is our priority of all..

OpenStudy (anonymous):

And the committee is of 3 persons, so in that, there can be at least one male employee..

OpenStudy (anonymous):

Hey, are you there? I need a response at least..

OpenStudy (anonymous):

yes sorry

OpenStudy (anonymous):

so would it be a combination problem?

OpenStudy (anonymous):

So, how can you form three member committee keeping atleast one male in it?

OpenStudy (anonymous):

5C2?

OpenStudy (anonymous):

The options can be: One Male and two females OR two males and one females OR Three males and no female.. I have got three, do you agree or you have any other option?

OpenStudy (anonymous):

but theres only 1 male....

OpenStudy (anonymous):

I am MAD..

OpenStudy (anonymous):

Kill me..

OpenStudy (anonymous):

So, we have 1 male and two females as our ONLY option..

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

So, 1 male to choose from 1 male only, and two females you can choose from 5 females. So: \[\implies ^5C_2 \times ^1C_1\]

OpenStudy (anonymous):

The later term comes out to be \(1\) only..

OpenStudy (anonymous):

so 10 right

OpenStudy (anonymous):

So, yes, Good, you were right, it is 5C2, and YES, it is 10..

OpenStudy (anonymous):

Good, thanks for teaching me.. :)

OpenStudy (anonymous):

\(\dagger\)

OpenStudy (anonymous):

awesome thanks

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