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$$ \small{ \sqrt{\frac {a^2+b^2+c^2}3} \geq \frac {a+b+c}3 \geq\sqrt[3]{abc} \geq \frac 3 { \frac 1a + \frac 1b + \frac 1c } \\ \\ \text{Here's how:}\\ \fbox{ \sqrt{\frac {a^2+b^2+c^2}3} \geq \frac {a+b+c}3 \geq\sqrt[3]{abc}}\\\fbox{ \geq \frac 3 { \frac 1a + \frac 1b + \frac 1c } } } $$
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