Question

Please help!
Factor
64v^2-49u^2

Answer 1

is this the answer (8v + 7u) * (8v - 7u)

Answer 2

hmm how did you get that anyway?

Answer 3

factor as a Difference of Squares

Answer 4

ok.. yeap, you're correct

Answer 5

so 64 is the square of 8, 49 is the square of 7, v2 is the square of v1, u2 is the square of u1
(8v + 7u) • (8v - 7u)

Answer 6

\(\bf 64v^2-49u^2\quad
\begin{cases}
64\to 8\cdot 8\to 8^2\\
\bf 49\to 7\cdot 7\to 7^2
\end{cases}
\\ \quad \\
64v^2-49u^2\implies (8^2v^2)-(7^2u^2)\implies (8v)^2-(7u)^2
\\ \quad \\
(8v-7u)(8v+7u)\)