Question

Help finishing off this integral

Answer 1

The original integral that I am working on \[\int\limits_{}^{}x^2 \tan ^{-1}x dx\]

And I set du = arctan u = 1/(1+ x^2) dv = x^2 and v = 1/3 x^3

Answer 2

so now I am left with the following

Answer 3

\[\int\limits_{}^{}\arctan(x)\frac{ 1 }{ 3 }x^3 - \frac{ 1 }{ 3 }\int\limits_{}^{}\frac{ x^3 }{ 1 + x^2 }\]

Answer 4

should I use u sub for that integral?

Answer 5

also forget that first integral sign

Answer 6

do I use divsion