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Trig question check
If csc=3/2 and pi/2
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Sin=2/3 use the pythagorean identity (2/3)^2+cos^2=1 cos^2=1-(2/3)^2 cos^2=5/9 cos=sqrt of 5/3 tan=sin/cos tan=
\[-\frac{ 2\sqrt{5} }{ 5 }\]
@bibby @Directrix
@Loser66 @SolomonZelman
i get most of it but my book says the answer is POSITIVE..
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i would think the domain here is the 2nd quadrant
|dw:1425952501694:dw|
\[\tan(\theta)=-\frac{2}{\sqrt5}\]
the minus because you are in quad 2
yep. knew something was wrong with my book, thanks
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