Question

The position function of a particle is s=t^3-12t, t>and equal to 0. Find the acceleration at the instant when the velocity is 0.

Answer 1

take the derivative twice

Answer 2

3t^2-12 = f' or velocity

6t= acceleration

Answer 3

3t^2=12

Answer 4

solve for t to find when the velocity is 0

Answer 5

t^2=4

t=2

Answer 6

acceleration = 6t

plug in 2 for t,

acceleration = 12

Answer 7

oh i see! thanks for your help! I didn't know that we need to figure the t.